regmatches {base} | R Documentation |
Extract or replace matched substrings from match data obtained by
regexpr
, gregexpr
or
regexec
.
regmatches(x, m, invert = FALSE) regmatches(x, m, invert = FALSE) <- value
x |
a character vector |
m |
an object with match data |
invert |
a logical: if |
value |
an object with suitable replacement values for the
matched or non-matched substrings (see |
If invert
is TRUE
(default), regmatches
extracts
the matched substrings as specified by the match data. For vector
match data (as obtained from regexpr
), empty matches are
dropped; for list match data, empty matches give empty components
(zero-length character vectors).
If invert
is FALSE
, regmatches
extracts the
non-matched substrings, i.e., the strings are split according to the
matches similar to strsplit
(for vector match data, at
most a single split is performed).
Note that the match data can be obtained from regular expression
matching on a modified version of x
with the same numbers of
characters.
The replacement function can be used for replacing the matched or
non-matched substrings. For vector match data, if invert
is
TRUE
, value
should be a character vector with length the
number of matched elements in m
. Otherwise, it should be a
list of character vectors with the same length as m
, each as
long as the number of replacements needed. Replacement coerces values
to character or list and generously recycles values as needed.
Missing replacement values are not allowed.
For regmatches
, a character vector with the matched substrings
if m
is a vector and invert
is FALSE
. Otherwise,
a list with the matched or non-matched substrings.
For regmatches<-
, the updated character vector.
x <- c("A and B", "A, B and C", "A, B, C and D", "foobar") pattern <- "[[:space:]]*(,|and)[[:space:]]" ## Match data from regexpr() m <- regexpr(pattern, x) regmatches(x, m) regmatches(x, m, invert = TRUE) ## Match data from gregexpr() m <- gregexpr(pattern, x) regmatches(x, m) regmatches(x, m, invert = TRUE) ## Consider x <- "John (fishing, hunting), Paul (hiking, biking)" ## Suppose we want to split at the comma (plus spaces) between the ## persons, but not at the commas in the parenthesized hobby lists. ## One idea is to "blank out" the parenthesized parts to match the ## parts to be used for splitting, and extract the persons as the ## non-matched parts. ## First, match the parenthesized hobby lists. m <- gregexpr("\\([^)]*\\)", x) ## Write a little utility for creating blank strings with given numbers ## of characters. blanks <- function(n) { vapply(Map(rep.int, rep.int(" ", length(n)), n, USE.NAMES = FALSE), paste, "", collapse = "") } ## Create a copy of x with the parenthesized parts blanked out. s <- x regmatches(s, m) <- Map(blanks, lapply(regmatches(s, m), nchar)) s ## Compute the positions of the split matches (note that we cannot call ## strsplit() on x with match data from s). m <- gregexpr(", *", s) ## And finally extract the non-matched parts. regmatches(x, m, invert = TRUE)