UCBAdmissions {datasets} | R Documentation |
Aggregate data on applicants to graduate school at Berkeley for the six largest departments in 1973 classified by admission and sex.
UCBAdmissions
A 3-dimensional array resulting from cross-tabulating 4526 observations on 3 variables. The variables and their levels are as follows:
No | Name | Levels |
1 | Admit | Admitted, Rejected |
2 | Gender | Male, Female |
3 | Dept | A, B, C, D, E, F |
This data set is frequently used for illustrating Simpson's paradox, see Bickel et al.\ (1975). At issue is whether the data show evidence of sex bias in admission practices. There were 2691 male applicants, of whom 1198 (44.5%) were admitted, compared with 1835 female applicants of whom 557 (30.4%) were admitted. This gives a sample odds ratio of 1.83, indicating that males were almost twice as likely to be admitted. In fact, graphical methods (as in the example below) or log-linear modelling show that the apparent association between admission and sex stems from differences in the tendency of males and females to apply to the individual departments (females used to apply more to departments with higher rejection rates).
This data set can also be used for illustrating methods for graphical display of categorical data, such as the general-purpose mosaic plot or the fourfold display for 2-by-2-by-k tables. See the home page of Michael Friendly (http://www.math.yorku.ca/SCS/friendly.html) for further information.
Bickel, P. J., Hammel, E. A., and O'Connell, J. W. (1975) Sex bias in graduate admissions: Data from Berkeley. Science, 187, 398–403.
require(graphics) ## Data aggregated over departments apply(UCBAdmissions, c(1, 2), sum) mosaicplot(apply(UCBAdmissions, c(1, 2), sum), main = "Student admissions at UC Berkeley") ## Data for individual departments opar <- par(mfrow = c(2, 3), oma = c(0, 0, 2, 0)) for(i in 1:6) mosaicplot(UCBAdmissions[,,i], xlab = "Admit", ylab = "Sex", main = paste("Department", LETTERS[i])) mtext(expression(bold("Student admissions at UC Berkeley")), outer = TRUE, cex = 1.5) par(opar)